Keewenaw Bay (Lake Superior) Lake Trout
The population biology of Lake Superior Lake Trout (Salvelinus namaycush) prior to 1950 was examined in detail by Sakagawa and Pycha (1971). In Table 1 of their paper, they presented the number of Lake Trout by age (from scales) collected in 4.5-inch mesh gillnets that were set between the Keweenaw Peninsula and Munising, MI in 1948. The numbers of Lake Trout caught for ages 3 to 14 were 5, 18, 21, 10, 45, 109, 95, 63, 42, 25, 13, and 4. Use these data to answer the questions below.
- Is this an example of a cross-sectional or longitudinal catch curve?
- Plot log(catch) versus age. Which ages best represent the descending portion of the catch curve? Explain.
- Using the catch-curve regression method, find the following (with 95% confidence intervals):
- Instantaneous total mortality rate.
- Annual total mortality rate.
- Annual survival rate.
- Mathematically show how to convert the instantaneous mortality rate to an annual mortality rate.
Stannard Rock (Lake Superior) Lake Trout
Curtis (1990) examined the population dynamics related to the recovery of an offshore Lake Trout population near Stannard Rock, Lake Superior. As part of this study, mortality rates were estimated from the relative abundance of Lake Trout longer than 43.2 cm. Relative abundance was recorded as the catch-per-unit-effort (CPE) of each age group in each year expressed as the number of fish caught per 50,000 m of 114.3 mm mesh gillnet. The results are shown in the table below. [Note: (1) the values in the table have been rounded to integers; (2) values recorded as “tr” in the original paper were recorded as “0.5” in this table; and (3) the years of capture are not contiguous (there is a break between 1959 and 1963 and again between 1969 and 1973).]
Year | VI | VII | VIII | IX | X | XI | XII | XIII | XIV |
---|---|---|---|---|---|---|---|---|---|
1959 | 64 | 219 | 241 | 121 | 33 | 9 | 1 | 0.5 | 1 |
…. | . | . | . | . | . | . | . | . | . |
1963 | 129 | 339 | 331 | 192 | 70 | 16 | 0.5 | 0.5 | 0.5 |
1964 | 149 | 524 | 515 | 201 | 63 | 18 | 2 | 0.5 | 0.5 |
1965 | 75 | 379 | 501 | 328 | 133 | 39 | 11 | 1 | 0.5 |
1966 | 149 | 488 | 459 | 172 | 64 | 22 | 5 | 0.5 | 0.5 |
1967 | 63 | 368 | 287 | 130 | 55 | 19 | 6 | 0.5 | 0.5 |
1968 | 50 | 215 | 259 | 141 | 55 | 18 | 5 | 1 | 0.5 |
1969 | 45 | 150 | 153 | 76 | 23 | 6 | 0.5 | 0.5 | 0.5 |
…. | . | . | . | . | . | . | . | . | . |
1973 | 101 | 759 | 1268 | 1116 | 491 | 141 | 40 | 4 | 0.5 |
1974 | 151 | 733 | 1114 | 1092 | 571 | 163 | 50 | 9 | 5 |
1975 | 109 | 901 | 1517 | 1606 | 1076 | 342 | 117 | 12 | 7 |
1976 | 53 | 604 | 1204 | 1560 | 1146 | 396 | 156 | 18 | 10 |
1977 | 157 | 867 | 1343 | 1410 | 1031 | 417 | 192 | 17 | 7 |
1978 | 89 | 735 | 1307 | 1623 | 1150 | 445 | 198 | 18 | 14 |
1979 | 29 | 299 | 718 | 1268 | 1195 | 585 | 300 | 36 | 14 |
Use these results to answer the following questions.
- What year-class of fish is represented by the 339 age-VII fish caught in 1963?
- Show the data frame of catches and corresponding ages for groups of fish.
- For fish captured in 1963.
- For fish of the 1963 year-class.
- The earliest year-class that is fully represented for ages IX through XII.
- The latest year-class that is fully represented for ages IX through XII.
- For each data frame created above, identify whether the data represent a cross-sectional or longitudinal catch curve?
- For the third data frame created above (earliest year class).
- Estimate, with 95% confidence interval, the instantaneous total mortality rate using the catch-curve regression method for ages IX through XII.
- Estimate, with 95% confidence interval, the annual total mortality rate using the catch-curve regression method for ages IX through XII. Carefully interpret this result.
- Repeat the previous question for last data frame created above (latest year class).
- Do you think the instantaneous mortality rates calculated for the earliest and latest year classes are statistically significantly different? Provide reasoning.